Question

A reasonably svelte Tarzan at 56.2 kg stands atop a branch in the African rain forest. He grabs this 28.7 m long vine and swings out. Initially the vine made an angle of 33.0° to the vertical. How fast will the mighty Lord of the Apes be traveling when he reaches the bottom of his swing?​

Answer 1

Assuming no air resistance and a constant downward vertical acceleration of 9.81 m/s2 due to gravity, Tarzan's speed at the bottom of the swing would be:

v = √(2 * 9.81 * 28.7 m / sin(2*33.0°)) = 45.0 m/s