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A 3000-lb wrecking ball hangs from a 10-ft cable of density 7 lb/ft attached to a crane. Calculate the work done if the crane lifts the ball from ground level to 10 ft in the air by drawing in the cable in ft-lbs

User Pretasoc
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Answer:

Explanation:

To calculate the work done by the crane in lifting the wrecking ball, we need to first calculate the gravitational potential energy of the ball before and after the lift, and then find the difference between them.

The gravitational potential energy (U) of an object of mass m at a height h above a reference level is given by the equation:

U = mgh

where g is the acceleration due to gravity, which is approximately 32.2 ft/s^2.

Before the lift, the ball is at ground level, so its height above the reference level is 0 ft. The mass of the ball is 3000 lbs, and we can calculate its initial gravitational potential energy as:

U_initial = (3000 lbs) x (32.2 ft/s^2) x (0 ft) = 0 ft-lbs

After the lift, the ball is 10 ft above the reference level, so its height is h = 10 ft. The length of the cable is also 10 ft, so the ball has been lifted a distance of 10 ft. The mass of the cable can be calculated as:

m_cable = (10 ft) x (7 lb/ft) = 70 lbs

The total mass that the crane has lifted is the sum of the mass of the ball and the mass of the cable:

m_total = 3000 lbs + 70 lbs = 3070 lbs

We can now calculate the final gravitational potential energy of the ball as:

U_final = (3070 lbs) x (32.2 ft/s^2) x (10 ft) = 9,932.4 ft-lbs

The work done by the crane in lifting the ball is the difference between the final and initial gravitational potential energies:

W = U_final - U_initial = 9,932.4 ft-lbs - 0 ft-lbs = 9,932.4 ft-lbs

Therefore, the work done by the crane in lifting the wrecking ball from ground level to 10 ft in the air is 9,932.4 ft-lbs.

User Hsming
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