Question

Please help!! If a rock is thrown upward on an exoplanet of a nearby star with initial velocity of 20, its height in

meters t seconds later is given by y = 20t - 1.87t².

Answer 1

To determine the height of the rock at a specific time, we need to substitute the time value into the equation y = 20t - 1.87t². For example, to find the height of the rock after 3 seconds, we substitute t = 3 into the equation:

y = 20(3) - 1.87(3)²

y = 60 - 16.83

y = 43.17

Therefore, the height of the rock after 3 seconds is 43.17 meters.