Question

Assuming the mass of the moon is 7.4 * 10 ^ 12 kg and its radius is 1.7 * 10 ^ 6 * m what is the gravitational energy of 1 kg mass at the moon's surface, Assuming R = 6.4 * 10 ^ 6 m. M- 6 * 10 ^ 24 kg. g = 9.8m / (s ^ 2) G = 6.7 * 10 ^ - 11​

Answer 1

1.620 m/s^2

Step-by-step explanation:

The acceleration due to gravity on the surface of the moon can be calculated using the formula:

g = G * M / R^2

where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the moon, and R is the radius of the moon.

Substituting the given values, we get:

g = (6.67 × 10^-11 Nm^2/kg^2) * (7.4 × 10^22 kg) / (17.4 × 10^6 m)^2

g = 1.62 m/s^2

Therefore, the acceleration due to gravity on the moon is approximately 1.62 m/s^2.