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At the last cinema showing, 245 tickets were sold. An adult ticket costs $8 and a child ticket costs $5. Determine how many children and adults attended the last session if the revenue was $1768?

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User Psyho
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Let's represent the number of adult tickets sold as "x" and the number of child tickets sold as "y".

We know that a single adult ticket costs $8, so the total revenue from adult ticket sales would be 8x. Similarly, a single child ticket costs $5, so the total revenue from child ticket sales would be 5y.

The total number of tickets sold was 245, so we can write an equation:

x + y = 245

We also know that the total revenue was $1768:

8x + 5y = 1768

We can use the first equation to solve for one of the variables in terms of the other:

y = 245 - x

Substitute this into the second equation:

8x + 5(245 - x) = 1768

Simplify and solve for x:

8x + 1225 - 5x = 1768

3x = 543

x = 181

So 181 adult tickets were sold. We can use the first equation to find the number of child tickets:

181 + y = 245

y = 64

So 64 child tickets were sold.

User Gorky
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