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A ball with an initial speed of 4.0 m/s undergoes constant acceleration at 3.0 m/s² for 5.0 s. What is the total distance traveled by the ball during this 5.0-s period?

A 38 m
B 58 m
C 75 m
D 95 m

User TheVinchi
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1 Answer

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To solve this problem, we can use the kinematic equation that relates the initial velocity, acceleration, time, and distance:

d = v₀t + 1/2at²

where d is the total distance traveled, v₀ is the initial velocity, a is the acceleration, and t is the time.

Substituting the given values into the equation, we get:

d = (4.0 m/s)(5.0 s) + 1/2(3.0 m/s²)(5.0 s)²

Simplifying and solving for d, we get:

d = 20.0 m + 37.5 m

d = 57.5 m

Therefore, the total distance traveled by the ball during the 5.0-s period is 57.5 meters.

B 58 m (rounded)
User Mmond
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