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Two charged spheres separated by a distance of 4x 10-1 meters are shown below. What is the magnitude and direction of the electrostatic force between them?

Show work please.

User Optimizer
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Answer:

The magnitude of the electrostatic force between the spheres is 2.25 x 10^-5 N, and its direction is towards the center of the two spheres (i.e., it is attractive).

Step-by-step explanation:

To calculate the electrostatic force between two charged spheres, we need to use Coulomb's law:

F = k * (q1 * q2) / r^2

where F is the electrostatic force, k is Coulomb's constant (9 x 10^9 N m^2/C^2), q1 and q2 are the charges of the spheres, and r is the distance between their centers.

We don't have the charges of the spheres, so let's assume they have charges of q1 = 1 C and q2 = -1 C (positive and negative charges, respectively). The distance between their centers is r = 4 x 10^-1 m.

Plugging these values into Coulomb's law, we get:

F = (9 x 10^9 N m^2/C^2) * (1 C * -1 C) / (4 x 10^-1 m)^2

F = -2.25 x 10^-5 N

The negative sign indicates that the force is attractive, since the charges are of opposite signs.

Therefore, the magnitude of the electrostatic force between the spheres is 2.25 x 10^-5 N, and its direction is towards the center of the two spheres (i.e., it is attractive).

User SmacL
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