Answer:
18. Two real solutions
Explanation:
Q 18
For a quadratic equation in standard form i.e. ax² + bx + c = 0
the discriminant is given by b² - 4ac
If the discriminant is 0, there is one real solution
If the discriminant is positive, there are two real solutions
If the discriminant is negative , there no real solutions
The given equation is:
x² - 8x = -14
Adding 14 to both sides
=> x² - 8x + 14 = 0
Comparing to the standard equation, we see
a = 1, b = -8, c = 14
Discriminant b² - 4ac = (-8)² - 4 x 1 x 14
= 64 - 56
= 10
Since discriminant is positive, there are two real solutions