Question

F c(x) = 4x – 2 and d(x) = x2 + 5x, what is (c circle d) (x)?

Answer 1

`16x^2-24x+9`

Explanation:

To find (c circle d)(x), we need to first find d(c(x)) and then simplify.

First, we need to find c(x) and substitute it into d(x), as follows:

d(c(x)) = d(4x - 2) = (4x - 2)^2 + 5(4x - 2)

Expanding the square and simplifying, we get:

d(c(x)) = 16x^2 - 24x + 9

Now, we have (c circle d)(x) = d(c(x)) = 16x^2 - 24x + 9.