Sure, here's a summarized and fun version:
Yo, let me tell you about this girl who threw a rock off a bridge horizontally with a speed of 12 m/s! It falls down and hits the water 2.28 seconds later. Now, let's find out two things:
First, how high is the bridge? To find out, we need to use the time it takes for the rock to fall and the acceleration due to gravity, which is 9.8 m/s². We can use the formula:
d = 1/2 * g * t²
Where d is the distance, t is the time, and g is the acceleration due to gravity. Plugging in the numbers, we get:
d = 1/2 * 9.8 m/s² * (2.28 s)² = 25.1 m
So, the bridge is 25.1 meters high.
Second, how far does the rock travel before hitting the water? Since there's no air resistance, the horizontal velocity of the rock remains constant. We can use the formula:
d = v * t
Where d is the distance, v is the velocity, and t is the time. Plugging in the numbers, we get:
d = 12 m/s * 2.28 s = 27.4 m
So, the rock travels 27.4 meters horizontally before hitting the water.
That's it, folks!