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The length of a rectangular poster is 4 more inches than two times its width. The area of the poster is 198 square inches. Solve for the dimensions (length and width) of the poster.​

User PyCthon
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Answer:

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Step-by-step explanation:givb

User Raja Reddy
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3 votes

Answer: L=22, W=9

Explanation:

The length of a rectangular poster is 4 more inches than two times its width. The area of the poster is 198 square inches. Solve for the dimensions (length and width) of the poster.

L=4+2W [Length] (1)

W=W [Width] (2)

P=2L+2W [perimeter] (3)

A=L*W = 198[area](4)

Subing (1) and (2) into (3) and (4)

P=2(4+2W)+2W

A=W(4+2W)

Simplify

P=8+4W+2W=8+6W

A=4W+2W^2=198

A=2W^2+4W-198

Set equal to 0 and solve for W

W=(-b+√(b^2-4ac))/2a

W=(-b-√(b^2-4ac))/2a

W=(-4+√(4^2-4(2)(-198)))/(2(2)) = 9

W=(-4-√(4^2-4(2)(-198)))/(2(2)) =-11

Disregard W =-11 since distance can’t be negative and keep W=9. Plug W=9 into Length equation (1)

L=4+2(9)=22

Final answer L=22 and W=9

User Torno
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