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Find the length of X

Find the length of X-example-1
User Yuta
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1 Answer

2 votes

Similar Triangles

Similar triangles have different dimensions, but their measurements have the same ratio.

Solving the Question

In the image, we can see two triangles. A large triangle and a small triangle. These are similar. How can we tell? They share the same angles.

Now, we can set up a proportion comparing their side lengths:


(82)/(28)=((2x+8)+(5x-4))/(2x+8)

Theoretically, if we divide corresponding side lengths of two similar shapes, we should get the same value. This is what makes the proportion true.

Now, simplify:


(82)/(28)=((2x+8)+(5x-4))/(2x+8)

  • First, simplify the fraction on the left:


(41)/(14)=((2x+8)+(5x-4))/(2x+8)

  • Remove the fractions by multiplying each side by the denominators:


41(2x+8)=14[(2x+8)+(5x-4)]

  • Expand the parentheses:


82x+328=14[2x+8+5x-4]\\82x+328=14(7x+4)\\82x+328=98x+56

  • Combine like terms:


328=16x+56\\272=16x\\x=17

Answer

x = 17

User TheBlackBenzKid
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