93.0k views
2 votes
Find the length of X

Find the length of X-example-1
User Yuta
by
7.9k points

1 Answer

2 votes

Similar Triangles

Similar triangles have different dimensions, but their measurements have the same ratio.

Solving the Question

In the image, we can see two triangles. A large triangle and a small triangle. These are similar. How can we tell? They share the same angles.

Now, we can set up a proportion comparing their side lengths:


(82)/(28)=((2x+8)+(5x-4))/(2x+8)

Theoretically, if we divide corresponding side lengths of two similar shapes, we should get the same value. This is what makes the proportion true.

Now, simplify:


(82)/(28)=((2x+8)+(5x-4))/(2x+8)

  • First, simplify the fraction on the left:


(41)/(14)=((2x+8)+(5x-4))/(2x+8)

  • Remove the fractions by multiplying each side by the denominators:


41(2x+8)=14[(2x+8)+(5x-4)]

  • Expand the parentheses:


82x+328=14[2x+8+5x-4]\\82x+328=14(7x+4)\\82x+328=98x+56

  • Combine like terms:


328=16x+56\\272=16x\\x=17

Answer

x = 17

User TheBlackBenzKid
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories