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Let A = {c, a, n, t, o, r } and B = {d, e, d, e, k, i, no, d}
State A \ B

User Neghez
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1 Answer

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Answer:

Explanation:

Set A \ B represents the set of elements that are in set A but not in set B. In this case, we can remove any elements in A that are also in B to get:

A \ B = {c, a, t, o, r}

Note that the elements "d" and "e" in set B are duplicated, but since we only need to remove them once from set A, they only count as one element in B.

In set theory, the backslash () symbol is used to represent the set difference operation. The set difference A \ B means the set of all elements that are in A but not in B.

In your example, A = {c, a, n, t, o, r } and B = {d, e, d, e, k, i, no, d}. To find A \ B, we need to identify all the elements in A that are not in B.

So, starting with set A, we see that the elements 'c', 'a', 'n', 't', 'o', and 'r' are in A. However, the elements 'd', 'e', 'k', 'i', 'no' are also in B, so we need to remove them from A.

After removing these elements from A, we are left with the set A \ B = {c, a, t, o, r}. These are the elements that are in A but not in B.

User VikingGlen
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