Question

Find the velocities of iron blocks weighing 50 kg and 100 kg if they are dropped from a height of 100 m at the same time.

Answer 1

44.294 m/s

you might want to double check the answer depending on what you use for g. some people use 9.81, some 9.8, and some 10. that can effect the final answer

Step-by-step explanation:

use the formula
`v^(2)-v_(0)^(2) = 2ax`, which can be moved around to get
`v = √(2ax)`

note that mass does not effect the velocity

since the blocks were dropped from rest, v_0 = 0m/s. a = g = 9.81 m/s^2, and x = h = 100m.

plug in the values for the variables to get v = sqrt(2(9.81)(100)) = 44.294 m/s for both blocks

Answer 2

44.3 m/s (both blocks)

Step-by-step explanation:

You want the velocity of iron blocks weighing 50 kg and 100 kg when they are dropped from a height of 100 m.

Velocity

When acceleration is from rest, the relation between velocity, acceleration, and distance is ...

v² = 2ad

The final velocity will be ...

v = √(2ad) = √(2·9.8·100) ≈ 44.3 . . . . meters per second

The velocity of each block will be about 44.3 m/s when it hits the ground.

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Additional comment

The formula used here is independent of mass, so the weight of the block is of no consequence. The formula also assumes air resistance is negligible, and that the acceleration due to gravity is constant over the distance. (The formula is derived by equating initial potential energy to final kinetic energy, assuming energy is conserved.)

The standard gravitational acceleration at the surface of the Earth is 9.80665 m/s². For school problems, 9.8, 9.81, or 10 are values commonly used. The actual value will vary by place, affected by latitude, altitude, and local geography.