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Where are the coordinates of the point on the directed line segment from (-6,-2) to (9,-7) that partitions the segment into a ratio of 3 to 2?

User Germanio
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1 Answer

3 votes

Answer:

the coordinates of the point that partitions the directed line segment from (-6,-2) to (9,-7) into a ratio of 3 to 2 are (0, -4).

Explanation:

To find the coordinates of the point that partitions the directed line segment from (-6,-2) to (9,-7) into a ratio of 3 to 2, we can use the following formula:

P = ( (2bx + 3ax)/(2+3) , (2by + 3ay)/(2+3) )

where P is the point we are looking for, (ax, ay) and (bx, by) are the coordinates of the two endpoints of the line segment, and the numbers 2 and 3 represent the ratio in which the line segment is to be divided.

Substituting the given values, we get:

P = ( (29 + 3(-6))/(2+3) , (2*(-7) + 3*(-2))/(2+3) )

= ( (18 - 18)/5 , (-14 - 6)/5 )

= ( 0, -4 )

Therefore, the coordinates of the point that partitions the directed line segment from (-6,-2) to (9,-7) into a ratio of 3 to 2 are (0, -4).

User Tim Eckel
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