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Relatively easy, maths word problem. Please make sure to include working out and try your best to give the correct answer and not a blank space just to get points.

Relatively easy, maths word problem. Please make sure to include working out and try-example-1
User RGilkes
by
7.0k points

2 Answers

0 votes

Answer:

68

Explanation:

We know that a cube has 8 corners. So that's 8 cubes just for the corners. We also know that a cube has 12 edges. An edge can be calculated by subtracting 2 from the side length. Since the side length is 7 cubes long, the edge length is 5 cubes long. The total number of cubes is:

N = (number of corner * cubes per corner) + (number of edges * cubes per edges)


N = (8 * 1) + (12 * 5) = 8 + 60 = 68

User Andrew Savinykh
by
7.7k points
0 votes

Answer:

68

Explanation:

Looking at the pattern of what is given for the bottom section. I can count two sections as being 6 blocks and then between those sections I would count 4 blocks. This would be true for the bottom and the top. The middle holding up the top and the bottom would need 4 more blocks for each "pillar"

2(6 + 6 + 4 + 4) + 4(4) = 56

If I use that same patter with the new structure

2(7 + 7 + 5 + 5) + 4(5) = 68

User Gautier
by
7.3k points