Question

Convert 6.94 mol Na2SO4 to mass of NaOH. Please round two digits after the decimal point. Pls don't forget the substances and units.

Balanced equation:
CaSO4+2NaOH--> Na2SO4+ Ca(OH)2

Thank you in advance!!

Answer 1

The given balanced equation is not relevant to the conversion of 6.94 mol Na2SO4 to the mass of NaOH. However, we can use stoichiometry to calculate the amount of NaOH required to react with 6.94 mol of Na2SO4.

From the balanced equation, we can see that 1 mole of Na2SO4 reacts with 2 moles of NaOH. Therefore, we can calculate the number of moles of NaOH required as follows:

Number of moles of NaOH = 6.94 mol Na2SO4 x (2 mol NaOH / 1 mol Na2SO4) = 13.88 mol NaOH

Now, we can use the molar mass of NaOH to calculate the mass of NaOH required:

Mass of NaOH = number of moles of NaOH x molar mass of NaOH

= 13.88 mol NaOH x 40.00 g/mol NaOH

= 555.20 g NaOH

Therefore, 6.94 mol of Na2SO4 requires 555.20 g of NaOH to react completely.

Note: It's important to specify the substances and units in the answer, as requested.