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PLS HELP(Identifying Functions LC) Which of the following tables represents a relation that is a function?

x y
2 −5
2 −3
2 0
2 3
2 5

x y
−3 0
−1 3
0 4
3 0
4 3

x y
−4 2
−3 2
0 −2
0 2
4 2

x y
−4 −2
−3 4
−1 −1
−1 2
3 −3

User Smeshko
by
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2 Answers

2 votes

Answer:

option 2 im doing it rn

Explanation:

User Matthew Son
by
6.4k points
1 vote

Answer:

Option 2

x y

−3 0

−1 3

0 4

3 0

4 3

Explanation:

For a relation x → y to be a function, there can be one and only one value of y for a value of x

Looking at the tables we see that option 1 is out since all x values are 2 andthere are multiple values of y

The last option is out because for x = 0 there are two values of y=-2 and y = 2

Correct choice is the second option which has a unique y value for each value of x

User Thindil
by
6.8k points