201k views
0 votes
I really need the answers now……

A spanner 15 cm long is used to tighten a nut which is pushing against a spring. The spring is exerting a force of 1,000N on the nut, and the screw is 30% efficient, with a pitch of 0.1 cm. What force is being exerted on the end of spanner?

User Gaborp
by
6.7k points

1 Answer

6 votes

Answer:

Approximately 500,000 N.

Step-by-step explanation:

We can start by using the equation for the efficiency of a screw:

efficiency = load / effort

where load is the force being exerted on the nut by the spring, and effort is the force being exerted on the end of the spanner. Solving for effort, we get:

effort = load / efficiency

Substituting the given values, we get:

effort = 1000 N / 0.3 = 3333.33 N

Next, we can use the equation for the mechanical advantage of a screw:

mechanical advantage = length of effort arm / pitch

where the length of the effort arm is the length of the spanner, and the pitch is the distance traveled by the screw for one complete turn. Substituting the given values, we get:

mechanical advantage = 15 cm / 0.1 cm = 150

Finally, we can use the formula for the relationship between force, effort, and mechanical advantage:

force = effort × mechanical advantage

Substituting the values we found, we get:

force = 3333.33 N × 150 = 499999.5 N

Therefore, the force being exerted on the end of the spanner is approximately 500,000 N.

User Lars Malmsteen
by
7.0k points