Question

A man pushes a lawn mower on a level lawn with a force of 211 N. If 50% of this force is directed forward, how much work is done by the man in pushing the mower 5.7 m?

Answer 1

W = 211 N * 0.5 * 5.7 m = 597.7 Nm.

Step-by-step explanation:

The work done by the man in pushing the mower is given by the equation, W = F * d, where F is the force applied and d is the displacement.

In this case, the force applied is 211 N, and the displacement is 5.7 m. Since only 50% of the force is directed forward, we can calculate the amount of work done by multiplying the force by 0.5.

Therefore, the work done by the man in pushing the mower is:

W = 211 N * 0.5 * 5.7 m = 597.7 Nm.