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1/√4+√5 + 1/√5+√6 + 1/√6+√7 + 1/√7+√8 + 1/√8+√9 =1​

User Sarangkkl
by
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1 Answer

3 votes

Hello,

Answer:

We can start by rationalizing the denominators of each fraction.

For the first fraction, we multiply the numerator and denominator by the conjugate of the denominator, which is √4 - √5:

1/√4+√5 = 1/√4+√5 × (√4 - √5)/(√4 - √5)

= (√4 - √5)/(4 - 5)

= (√4 - √5)/(-1)

For the second fraction, we multiply the numerator and denominator by √5 - √6:

1/√5+√6 = 1/√5+√6 × (√5 - √6)/(√5 - √6)

= (√5 - √6)/(5 - 6)

= (√5 - √6)/(-1)

We can do the same for the remaining fractions:

1/√6+√7 = (√6 - √7)/(-1)

1/√7+√8 = (√7 - √8)/(-1)

1/√8+√9 = (√8 - √9)/(-1)

Now we can simplify the expression:

1/√4+√5 + 1/√5+√6 + 1/√6+√7 + 1/√7+√8 + 1/√8+√9

= (√4 - √5)/(-1) + (√5 - √6)/(-1) + (√6 - √7)/(-1) + (√7 - √8)/(-1) + (√8 - √9)/(-1)

= (√4 - √5 + √5 - √6 + √6 - √7 + √7 - √8 + √8 - √9)/(-1)

= (√4 - √9)/(-1)

= √9 - √4

= 3 - 2

= 1

Therefore, the expression simplifies to 1, which is equal to the right-hand side of the equation.

Good luck

User Abathur
by
7.5k points