Question

A worker pushes horizontally on a large crate with a force of 235 N, and the crate is moved 3.3 m. How much work was done?

Answer 1

Hello,

Answer:

The work done by a force on an object is given by:

Work = Force x Distance x cos(theta)

where Force is the magnitude of the force applied, Distance is the displacement of the object, and theta is the angle between the force and displacement vectors. Since the worker is pushing horizontally on the crate, the angle between the force and displacement vectors is zero degrees, and cos(0) = 1.

So, the work done by the worker is:

Work = Force x Distance x cos(theta)

Work = 235 N x 3.3 m x cos(0)

Work = 773.5 J

Therefore, the work done by the worker on the crate is 773.5 J.

Good luck !

Answer 2

Step-by-step explanation:

The work done by a force on an object is equal to the product of the magnitude of the force, the distance moved by the object in the direction of the force, and the cosine of the angle between the force and the direction of motion.

In this case, the worker pushes the crate horizontally, so the force and the direction of motion are in the same direction. Therefore, the angle between them is 0 degrees, and the cosine of the angle is 1.

The work done by the worker on the crate is then:

work = force x distance x cos(angle)

= 235 N x 3.3 m x cos(0)

= 773.5 J

So the work done by the worker is 773.5 Joules (J).