Answer:
Step-by-step explanation:
First, we need to find the moles of CO2 that will be produced by using the given mass:
59.4 kg CO2 = 59400 g CO2
moles CO2 = 59400 g / 44.01 g/mol = 1349.2 mol CO2
According to the balanced chemical equation, 1 mole of heptane produces 7 moles of CO2. Therefore, the moles of heptane required can be calculated as:
moles heptane = moles CO2 / 7 = 1349.2 mol / 7 = 192.74 mol
Next, we can use the ideal gas law to calculate the volume of heptane gas at the given conditions:
PV = nRT
where P = 29.8 inHg = 1.011 atm (converted using 1 atm = 29.92 inHg), V is the volume we want to find, n = 192.74 mol, R = 0.082057 L atm/mol K, and T = 129.0°C = 402.15 K (converted using Kelvin = Celsius + 273.15).
Solving for V, we get:
V = nRT / P = (192.74 mol)(0.082057 L atm/mol K)(402.15 K) / 1.011 atm = 6573 L
Therefore, the volume of heptane gas required is 6573 L at the given conditions.