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I want to build a rectangular garden so that the length is 45 meters more than twice the width. I have 1350 meters of fencing available. What dimensions should I make the garden?

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Answer:

Explanation:

Let's start by defining the variables for the problem. Let's say that:

w = the width of the rectangular garden (in meters)

l = the length of the rectangular garden (in meters)

We know that the length is 45 meters more than twice the width, so we can write:

l = 2w + 45

We also know that we have 1350 meters of fencing available to enclose the rectangular garden. The perimeter of the rectangular garden is equal to the sum of the lengths of all four sides. Since there are two sides of length w and two sides of length l, we can write:

Perimeter = 2w + 2l

Substituting the expression for l that we derived earlier, we get:

Perimeter = 2w + 2(2w + 45)

Perimeter = 6w + 90

We know that the perimeter of the rectangular garden is equal to 1350 meters, so we can write:

1350 = 6w + 90

Solving for w, we get:

6w = 1260

w = 210

Now that we know the value of w, we can use the expression for l that we derived earlier to find the length:

l = 2w + 45

l = 2(210) + 45

l = 465

Therefore, the dimensions of the rectangular garden should be 210 meters by 465 meters.