Question

3. A bumblebee of mass 0.015 kg is traveling at 21.0 m/sec when it collides with a windshield. How much kinetic energy does the bee have as it hits the windshield? Show work thanks for the help

Answer 1

The kinetic energy of the bumblebee as it hits the windshield is given by the equation KE = 0.5 x 0.015 kg x (21.0 m/s) squared. This gives us a total of 945 J of kinetic energy.

Answer 2

Explanation:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.

We are given the mass of the bumblebee as 0.015 kg and its velocity as 21.0 m/sec. We can plug these values into the formula to calculate its kinetic energy:

KE = (1/2) * m * v^2

= (1/2) * 0.015 kg * (21.0 m/sec)^2

= (1/2) * 0.015 kg * 441.0 m^2/sec^2

= 2.92625 J

Therefore, the bumblebee has 2.92625 Joules of kinetic energy as it hits the windshield.