Question

5. A cliff-jumper of mass 68.0 kg stands on the edge of a cliff and possesses 16,800 J of potential energy. How high up is this lunatic from the base of the cliff?

Answer 1

h

Explanation:

Answer 2

The potential energy of an object is given by the equation:

PE = mgh

where PE is potential energy, m is mass, g is the acceleration due to gravity, and h is the height.

Rearranging this equation, we get:

h = PE / (mg)

Substituting the given values, we get:

h = 16800 J / (68.0 kg x 9.81 m/s^2)

h = 24.8 meters

Therefore, the cliff-jumper is standing 24.8 meters above the base of the cliff.