Question

Could someone explain how to solve this?

If a 1,300 kg car is moving at 27 m/s when it hits a truck, resulting in a 21,000 N force that slows the car down to 15 m/s, for how long did the car experience the force?

Answer 1

Step-by-step explanation:

We can use the equation:

$F = ma$

where F is the force, m is the mass, and a is the acceleration.

To find the acceleration, we can use:

$a = \frac{\Delta v}{\Delta t}$

where $\Delta v$ is the change in velocity and $\Delta t$ is the time interval.

Rearranging the first equation, we get:

$t = \frac{m\Delta v}{F}$

Substituting the given values, we get:

$t = \frac{(1300\text{ kg})(15\text{ m/s} - 27\text{ m/s})}{21000\text{ N}} \approx 1.86\text{ s}$

Therefore, the car experienced the force for about 1.86 seconds.