Question

A rm has 10'6"×14 dimensions. what is the perimeter of the room?

Answer 1

Perimete23.33 feet

Step-by-step explanation:

A room is like a rectngle. SO we would apply the perimeter of a rectangle

perimeter of a rectangle = 2(length + width)

length = 10'6" = 10 feet 6 inches

Width = 14' = 14 inches

Let's make the unit oof length and width to be in feet (that is the unit in the question option)

12 inches = 1 foot

6 inches = 6/12 = 1/2 feet

14 inches = 14/12 = 7/6 feet

length = 10 feet + 1/2 feet = 10 1/2 feet = 21/2 feet

width = 7/6 feet

perimeter of a rectangle = 2(21/2 + 7/6)

`\begin{gathered} \text{perimeter = 2(}(21)/(2)+\text{ }(7)/(6))\text{ = 2(}(3(21)+7))/(6) \\ \text{Perimeter = 2(}(63+7)/(6)) \end{gathered}`
`\begin{gathered} \text{perimeter = 2(}(70)/(6))\text{ = 140/6} \\ \text{perimeter = 23.33 f}eet \end{gathered}`