Question

Light traveling in air strikes a flat piece of uniformly thick glass at an incident angle of 60.0, as shown in the figure on the right. If the index of refraction of the glass is 1.50

, what is the angle of refraction in the glass, what is the angle at which ray emerges from the glass?.

Answer 1

the angle at which the ray emerges from the glass is approximately 26.8°.

Step-by-step explanation:

Assuming that the angle of incidence is measured from the normal, the angle of incidence of the light ray in air is 60.0°. Using Snell's law, we can find the angle of refraction in the glass:

n1 sinθ1 = n2 sinθ2

where n1 is the refractive index of air, which is approximately 1, and n2 is the refractive index of the glass, which is given as 1.50. Therefore, we have:

1.00 sin 60.0° = 1.50 sinθ2

θ2 ≈ 40.9°

So the angle of refraction in the glass is approximately 40.9°.

To find the angle at which the ray emerges from the glass, we need to apply Snell's law again using the angle of incidence in the glass and the refractive index of air:

n2 sinθ2 = n1 sinθ3

where θ3 is the angle of refraction in air. Plugging in the values, we get:

1.50 sin 40.9° = 1.00 sinθ3

θ3 ≈ 26.8°

So the angle at which the ray emerges from the glass is approximately 26.8°.