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If a² + a -½= 5 and a½ - a½ >0, calculate the value of (1) a+a¹ ​

User Pre
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1 Answer

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Answer:

we can find a + a^(1/2) by substitution:

a + a^(1/2) = 6/5 + √(6/5)

Explanation:

We have the equation:

a² + a - 1/2 = 5

Adding 1/2 to both sides:

a² + a = 5 1/2

Factoring out a from the left-hand side:

a(a + 1) = 5 1/2

Taking the square root of both sides:

a + 1/2 = ±√(5 1/2 / a)

Since a^(1/2) - a^(1/2) > 0, we know that a is positive, so we can discard the negative root. Then we have:

a + 1/2 = √(5 1/2 / a)

Squaring both sides:

a² + a + 1/4 = 5 1/2 / a

Substituting the expression for a² + a from the first equation:

5 1/2 - 1/2 + 1/4 = 5 1/2 / a

Multiplying both sides by a:

5 1/2 a - 1/2 a + 1/4 a = 5 1/2

Simplifying:

5a - 1/2 = 5 1/2

Adding 1/2 to both sides:

5a = 6

Dividing by 5:

a = 6/5

Finally, we can find a + a^(1/2) by substitution:

a + a^(1/2) = 6/5 + √(6/5)

User Ben Lings
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