Answer:
Therefore, the work done on the 45.6 kg rock that you lift 0.85 m is approximately 380.75 Joules.
Step-by-step explanation:
The work done on an object is given by the formula:
work = force x distance x cos(theta)
where force is the applied force on the object, distance is the distance the object is moved, and theta is the angle between the force and the direction of motion. In this case, we can assume that the angle between the force and the direction of motion is zero degrees, since you are lifting the rock straight up.
The force required to lift the rock is equal to its weight, which is given by:
force = mass x gravity
where mass is the mass of the rock and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2 on the surface of the Earth.
Substituting the given values, we get:
force = 45.6 kg x 9.81 m/s^2 = 447.936 N
Now we can calculate the work done:
work = force x distance x cos(theta) = 447.936 N x 0.85 m x cos(0) = 380.7464 J
Therefore, the work done on the 45.6 kg rock that you lift 0.85 m is approximately 380.75 Joules.