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Cedric also put 18 rocket stickers and 24 airplane stickers in equal groups. whay is the greatest number of groups Cedric could have made? How many of each type of sticker did he put in the group. please show work!​

User Kpogue
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1 Answer

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To find the greatest number of equal groups Cedric could have made, we need to find the greatest common factor (GCF) of 18 and 24.

The prime factorization of 18 is 2 × 3².

The prime factorization of 24 is 2³ × 3.

To find the GCF, we need to take the product of all the common factors and the lowest exponent of each factor that is common to both numbers. In this case, the common factor is 2 and the lowest exponent is 1.

GCF(18, 24) = 2¹ = 2

So Cedric could have made up to 2 equal groups of stickers.

To find how many of each type of sticker he put in each group, we can divide the number of stickers by the number of groups.

For the rocket stickers, Cedric put 18 stickers in 2 groups, so he put 9 rocket stickers in each group.

For the airplane stickers, Cedric put 24 stickers in 2 groups, so he put 12 airplane stickers in each group.

Therefore, Cedric put 9 rocket stickers and 12 airplane stickers in each of the 2 groups he made.

User Bjhend
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