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A sample of oxygen gas initially at 323 K was heated to 377 K. If the volume of the oxygen gas sample at 377 K is 753.8 mL,

what was its volume at 323 K?

User Tanuki
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ANSWER : 643.1 mL

STEPS:

V1/T1 = V2/T2

Volume of oxygen gas.

A sample of oxygen gas was initially at a temperature of 323 K.

The sample was heated to a new temperature of 377 K.

The volume of the sample at the new temperature of 377 K is 753.8 mL.

We want to find the volume of the sample at the initial temperature of 323 K.

To solve for the initial volume, we can use the combined gas law:

(V1/T1) = (V2/T2), where:

V1 is the initial volume of the gas

T1 is the initial temperature of the gas

V2 is the final volume of the gas

T2 is the final temperature of the gas

Rearranging the equation to solve for V1, we get: V1 = (V2/T2) x T1

Plugging in the values we know, we get:

V1 = (753.8 mL / 377 K) x 323 K

Solving for V1, we get:

V1 = 643.1 mL

Therefore, the volume of the oxygen gas sample at 323 K is approximately 643.1 mL.

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User Nicholas Betsworth
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