Question

an object is thrown vertically upward with a certain initial velocity in a world where the acceleration due to gravity is 19.6 m/s2. neglecting air resistance, the height to which this object will rise in this world is

Answer 1

S = H = V0 t + 1/2 g t^2 this is a vector equation with V0 positive and

g is negative - this will give height H

Another way to look at this is to find t if one knows V0

t = V0 / g would be the time for an object to "fall" from zero speed to the speed it originally had (conservation of energy - rise time = fall time)

Then S = 1/2 g t^2