Answer:
a) the pressure and temperature of the mixture after the compression are approximately 8.13x105 N/m² and 439 K, respectively.
b)the work done by the mixture is zero.
Step-by-step explanation:
we can use the ideal gas law and the adiabatic compression equation.
a) Using the ideal gas law, we can find the initial number of moles of gas-air mixture in the cylinder:
PV = nRT
n = PV/RT = (1.00x105 N/m²)(240 cm³/1000 cm³/m³)/(8.31 J/mol•K)(20+273 K) ≈ 0.027 mol
Since the mixture is compressed adiabatically, we can use the adiabatic compression equation to find the final pressure and temperature:
P1V1^γ = P2V2^γ
where γ = Cp/Cv is the ratio of specific heats of the mixture.
Assuming the gas-air mixture behaves as a diatomic gas, we can use the values γ = 1.4 and Cp = 29.1 J/mol•K and Cv = 20.8 J/mol•K.
Substituting the given values, we can solve for the final pressure and temperature:
P2 = P1(V1/V2)^γ = (1.00x105 N/m²)(240 cm³/40 cm³)^1.4 ≈ 8.13x105 N/m²
T2 = T1(V1/V2)^(γ-1) = (20+273 K)(240 cm³/40 cm³)^0.4 ≈ 439 K
Therefore, the pressure and temperature of the mixture after the compression are approximately 8.13x105 N/m² and 439 K, respectively.
b) The work done by the mixture during the compression can be found using the equation:
W = -ΔU
where ΔU is the change in internal energy of the mixture.
Since the compression is adiabatic, there is no heat transfer and ΔU = Q = 0.
Therefore, the work done by the mixture is zero.