Answer:
89.6 L
Step-by-step explanation:
The volume of a gas at STP (Standard Temperature and Pressure) is 22.4 L per mole of gas. To determine the volume of 128 grams of O2, we need to convert the mass of O2 to moles of O2:
First, we need to determine the number of moles of O2 in 128 grams of O2 using the molar mass of O2:
molar mass of O2 = 2 x atomic mass of O = 2 x 16.00 g/mol = 32.00 g/mol
moles of O2 = mass of O2 / molar mass of O2
moles of O2 = 128 g / 32.00 g/mol = 4.00 mol
Now that we have the number of moles of O2, we can use the volume at STP for one mole of gas to calculate the total volume of the sample:
volume of O2 = number of moles of O2 x volume at STP per mole of gas
volume of O2 = 4.00 mol x 22.4 L/mol = 89.6 L
Therefore, 128 grams of O2 at STP occupies a volume of 89.6 L.