Question

How do you find the slope of the tangent line to the parabola y=7x−x2at the point (1,6)?

Answer 1

The derivative is y’ = 7 - 2x so the slope is y’ (1) = 7 - 2 = 5.

if you want the equation of the tangent line, just use the fact that y(1) = 6 to write it as y = 5 (x - 1) + 6 = 5x + 1

therefore, the derivative of y = ax2 + bx + c is y’ = 2ax + b!

hope this help!!!!