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A bee flies from a petunia to a marigold at an average speed of 3 meters per second. Immediately upon reaching the marigold the bee turns around and flies back to the petunia at an average speed of 6 meters per second, following his original path. What was the bee’s average speed for the round trip?

1 Answer

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Answer:

Step-by-step explanation:

2 ways to answer this: speed is a scalar, velocity is a vector

Speed: (3+6)/2 = 4.5 m/s

Velocity: (3-6)/2 = -1.5 m/s define the positive direction as the one TO the marigold, negative direction is the one from the marigold back to the petunia

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