Question

A 2-kg mass placed 30-cm to the

left of the fulcrum is balanced by

a 1-kg mass placed ______ cm to

the right of the fulcrum

Answer 1

60 cm

Step-by-step explanation:

Torque = τ = rFsinΘ

In this case Θ = 90, so sinΘ = 1

x = distance from fulcrum of the 1 kg mass

(2 kg)(g)(0.30 m) = (1 kg)(g)(x) because the beam is in equilibrium

0.60 N·m = (1 N)x

x = 0.60 m = 60 cm