Answer:
2.637 L
Step-by-step explanation:
The volume of oxygen O2 found in 41.1 grams of oxygen at STP can be calculated using the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles of oxygen, R is the ideal gas constant, and T is the temperature.
Using the molar mass of oxygen, which is 32 g/mol, we can calculate the number of moles of oxygen in 41.1 g of oxygen:
n = 41.1 g/ 32 g/mol = 1.28125 moles
At STP, the pressure is 101.325 kPa and the temperature is 273.15 K. Plugging these values into the ideal gas law equation gives us:
V = (1.28125 mol)(0.08206 L•atm/mol•K)(273.15 K) / (101.325 kPa) = 2.637 L