Question

A gas has a volume of 28 L in a temperature of of 85°C has its volume increased 42 L and its temperature decrease to 47°C if I measure the pressure after the change to be 2.0 Atm what is the original pressure of the gas?

Answer 1

Below

Step-by-step explanation:

"has its volume increased 42 L" <===so final volume is 48+28 (as written)

P1V1 / T1 = P2V2 / T2 T must be in Kelvin (add 273.15 to °C)

Looking for P1

Re-arrange

P1 = P2 V2 / T2 * T1 / V1 sub in the values

P1 = (2)(42+28) / (47+ 273.15) * (85+273.15) /(28)

P1 = 5.59 atm