213k views
2 votes
a 25 foot ladder is leaned against the side of a building 2 feet from the base of the building. how far up the wall does the ladder reach and what is the angle of elevation for the ladder both to the nearest tenth?

User Nimrodm
by
6.7k points

1 Answer

1 vote

Answer:

The ladder reaches up to 23.2 feet up the side of the building and the angle of elevation is 78.7 degrees to the nearest tenth. To calculate these values, you can use the Pythagorean Theorem. Let x be the distance the ladder reaches up the wall, and let y be the distance from the base of the building to where the ladder is leaning against the wall. Then, the Pythagorean Theorem states that x2 + y2 = 252, or x2 = 252 - y2. Since y = 2, then x2 = 252 - 22 = 676. Solving for x gives us x = 26, so the ladder reaches up to 26 feet. To calculate the angle of elevation, we can use trigonometry. We know that the opposite side is 26 feet and the adjacent side is 2 feet, so by using the tangent function, we can calculate the angle of elevation as tan-1(26/2) = 78.7 degrees.

User Ofirule
by
7.8k points