Answer:
Explanation:
Given AB = AC = BC (all sides of equilateral triangle are equal)
BC = 6y + 4
AD = 4y
as D is midpoint of AB, so AB = 2 x 4y = 8y
Since AB = BC
Hence, 8y = 6y + 24
Or, 8y - 6y = 24
Or, 2y = 24
Or, y = 24/2 = 12
Now, Angle ACB = 60 degree (all angles of an equilateral triangle measure 60 degree)
And CD being bisector of side opposite C so it is angular bisector of angle ACB
So, angle ACD = 1/2 of angle ACB
Or, 4x + 2 = 30
Or, 4x = 30 - 2 = 28
Or, x = 28/4 = 7 degree