Question

Mrs. Neer wants to position four of her students (A, B, C and D) in line for the assembly. How many possibilities can she get?

Answer 1

There can be possible of 24 combos

Answer 2

24

Explanation:

Formula is number of possibilities = n (n-1) (n-2) ....1

Here, n = 4

So, number of possibilities = 4 x 3 x 2 x 1 = 24

You can also use following method to count:

ABCD

ABDC

ACBD

ACDB

ADBC

ADCB

--------

BACD

BADC

BCAD

BCDA

BDAC

BDCA

---------

CABD

CADB

CBAD

CBDA

CDAB

CDBA

--------

DABC

DACB

DBAC

DBCA

DCAB

DCBA

--------

Total 24 combinations