Question

Which of the following is the best linear approximation for f(x) = cos(x) near x equals pi divided by 2 ?

y equals x minus pi over 2
y equals negative x plus pi over 2
y equals negative x plus pi over 2 plus 1
y equals x minus pi over 2 plus 1

Answer 1

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Explanation:

The best linear approximation for f(x) = cos(x) near x = pi/2 is given by the equation:

y = -(x - pi/2) + 1

This is because the linear approximation should have the same value and slope as the original function at x = pi/2.

At x = pi/2, the value of f(x) = cos(pi/2) = 0. The value of the linear approximation at x = pi/2 is:

y = -(pi/2 - pi/2) + 1 = 1

So, the value of the linear approximation matches the value of the original function at x = pi/2.

The slope of the original function at x = pi/2 is -sin(pi/2) = -1. The slope of the linear approximation is:

y' = -1

So, the slope of the linear approximation also matches the slope of the original function at x = pi/2.

Therefore, the best linear approximation for f(x) = cos(x) near x = pi/2 is:

y = -(x - pi/2) + 1

Hence, the correct option is "y equals negative x plus pi over 2 plus 1".

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