Question

2 LiOH(s) + CO2(g) à Li2CO3(s) + H2O(l)

If you have 655 grams of lithium hydroxide:
1. What is the actual mole ratio?
2. What is the actual gram ratio?
3. What mass of CO2 can 655 g LiOH absorb?
4. What mass of H2O will be available for use?

Answer 1

Approx. 1200g

Step-by-step explanation:

You have given the stoichiometric equation:

2LiOH(s)+CO2(g)→Li2CO3(s)+H2O(l)

.And this unequivocally tells us that each mole of carbon dioxide required 2 moles of lithium hydroxide:

Moles of LiOH = 1.3×103⋅g/23.95⋅g⋅mol−1=54.3⋅mol

And thus

27.1⋅mol

CO2 can be absorbed:

27.×44.01gmol−1≅1.2 kg

Step-by-step explanation: