Question

For the reaction of sulfur dioxide and oxygen to produce sulfur trioxide, shown below, what is the equilibrium concentration of sulfur dioxide, SO2, if the equilibrium concentrations of O2 and SO3 are 0.12 M and 0.015 M, respectively?

2 SO2(g) + O2(g) ⇄ 2 SO3(g) K = 1.5

Answer 1

The equilibrium concentration of SO2 is approximately 0.111 M.

Step-by-step explanation:

The equilibrium constant, K, can be calculated using the equilibrium concentrations of the reactants and products. In this case, the equilibrium concentrations of O2 and SO3 are given as 0.12 M and 0.015 M respectively, and we need to find the equilibrium concentration of SO2. By rearranging the equilibrium expression and substituting the given values, we can solve for the equilibrium concentration of SO2:

K = [SO3]^2 / ([SO2]^2[O2])

1.5 = (0.015)^2 / ([SO2]^2(0.12))

Solving for [SO2], we find that the equilibrium concentration of SO2 is approximately 0.111 M.