Question

A freight train traveling at a speed of 18.0 m/s begins braking. The train's acceleration while breaking is -0.33 m/s^2. What is the train's speed after 23.0 seconds?

Answer 1

The train's speed after 23.0 seconds of braking is approximately 9.41 m/s.

Step-by-step explanation:

Using the kinematic equation:

v_f = v_i + a*t

where:

v_f = final velocity (what we are trying to find)

v_i = initial velocity (18.0 m/s)

a = acceleration (-0.33 m/s^2)

t = time (23.0 s)

Plugging in the values:

v_f = 18.0 m/s + (-0.33 m/s^2)*(23.0 s)

v_f = 9.41 m/s