Answer:
124 grams of Na2O are required to produce 160 grams of NaOH.
Step-by-step explanation:
The balanced chemical equation is: Na2O + H2O -> 2NaOH
From the equation, we can see that 1 mole of Na2O produces 2 moles of NaOH.
To find the amount of Na2O required to produce 160 grams of NaOH, we need to first calculate the number of moles of NaOH:
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Number of moles of NaOH = mass / molar mass = 160 g / 40 g/mol = 4 moles
Since 1 mole of Na2O produces 2 moles of NaOH, we need half as many moles of Na2O, which is 2 moles.
Finally, we can calculate the mass of Na2O required:
Molar mass of Na2O = 23 + 23 + 16 = 62 g/mol
Mass of Na2O = number of moles * molar mass = 2 moles * 62 g/mol = 124 g
Therefore, 124 grams of Na2O are required to produce 160 grams of NaOH.