Answer:
To solve the inequality |h + 3| < 5, we need to consider two cases, depending on whether the expression inside the absolute value bars is positive or negative:
Case 1: h + 3 >= 0
If h + 3 >= 0, then we can remove the absolute value bars without changing the inequality:
h + 3 < 5
Subtracting 3 from both sides, we get:
h < 2
So the solution for this case is h < 2.
Case 2: h + 3 < 0
If h + 3 < 0, then the inequality becomes:
-(h + 3) < 5
Multiplying both sides by -1 (and reversing the inequality), we get:
h + 3 > -5
Subtracting 3 from both sides, we get:
h > -8
So the solution for this case is h > -8.
Putting these two solutions together, we have:
-8 < h < 2
Therefore, the solution set in set-builder notation is:
h