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Solve |h+3|<5. Write the solution set using set-builder notation.

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Answer:

To solve the inequality |h + 3| < 5, we need to consider two cases, depending on whether the expression inside the absolute value bars is positive or negative:

Case 1: h + 3 >= 0

If h + 3 >= 0, then we can remove the absolute value bars without changing the inequality:

h + 3 < 5

Subtracting 3 from both sides, we get:

h < 2

So the solution for this case is h < 2.

Case 2: h + 3 < 0

If h + 3 < 0, then the inequality becomes:

-(h + 3) < 5

Multiplying both sides by -1 (and reversing the inequality), we get:

h + 3 > -5

Subtracting 3 from both sides, we get:

h > -8

So the solution for this case is h > -8.

Putting these two solutions together, we have:

-8 < h < 2

Therefore, the solution set in set-builder notation is:

h

User Ross Hettel
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